Jump to content
We've recently updated our Privacy Statement, available here ×

tcenes

Members
  • Posts

    5
  • Joined

  • Last visited

 Content Type 

Profiles

Forum

Events

Featured Visualizations

Knowledge Base

Documentation (PDF Downloads)

Blog

Documentation (Test Area)

Documentation

Dr. Jaspersoft Webinar Series

Downloads

Everything posted by tcenes

  1. Got it, the "names" dont need any kind of '', "" or []. Just the Strings need 'STRING'.
  2. Hi, i put in the Else-Value but theres always the error message again.
  3. Hmm i'm not sure what can be wrong. select CASE WHEN einzelaufstellung.Zahlungsart = 'banktransfer' THEN 'Lastschrift' WHEN einzelaufstellung.Zahlungsart = 'eustandardtransfer' THEN 'Vorkasse' WHEN einzelaufstellung.Zahlungsart = 'invoice' THEN 'Rechnung' WHEN einzelaufstellung.Zahlungsart = 'paypal' THEN 'Paypal' WHEN einzelaufstellung.Zahlungsart = 'paypalexpress' THEN 'Paypalexpress' END as [Zahlungsart],einzelaufstellung.Anzahl as [Anzahl der Aufträge],einzelaufstellung.Anzahl/gesamtzahl.Anzahl*100 as [Anteil der Aufträge in %],einzelaufstellung.Umsatz as [umsatz in EUR],einzelaufstellung.Umsatz/gesamtzahl.Umsatz*100 as [Anteil des Umsatzes in %]from( SELECT '1' as [joinid], o.payment_method as [Zahlungsart], count(o.orders_id) as [Anzahl], sum(ot.value) as [umsatz] FROM orders as o LEFT OUTER JOIN orders_total as ot ON o.orders_id = ot.orders_id and class = "ot_total" LEFT OUTER JOIN customers as c ON o.customers_id=c.customers_id GROUP BY o.payment_method) as einzelaufstellungLEFT OUTER JOIN( SELECT '1' as [joinid], count(o.orders_id) as [Anzahl], sum(ot.value) as [umsatz] FROM orders as o LEFT OUTER JOIN orders_total as ot ON o.orders_id = ot.orders_id and class = "ot_total") as gesamtzahl ON einzelaufstellung.joinid = gesamtzahl.joinidorder by [Zahlungsart] ASC[/code]
  4. Hallo, always if i try to fill a report i get the "Error executing SQL statement" Message and i cant understand why. Thanks for your Help.
×
×
  • Create New...